X^2+43x-90=0

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Solution for X^2+43x-90=0 equation: 



X^2+43X-90=0

a = 1; b = 43; c = -90;
Δ = b2-4ac
Δ = 432-4·1·(-90)
Δ = 2209
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{2209}=47$


$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(43)-47}{2*1}=\frac{-90}{2}
=-45
$


$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(43)+47}{2*1}=\frac{4}{2}
=2
$

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